1, 5, 9, 15, 25, 37, 49

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 15
The terms of the given series are $1^{2}, (2^{2} + 1), 3^{2}, (4^{2} . . + 1), 5^{2}, (6^{2} + 1), 7^{2}$ .
So, 15 is wrong and must be replaced by $(4^{2} + 1)$ i.e. 17.

Suggest Corrections

Similar questions

Simplify:
$(\frac{- 4}{5} \times \frac{15}{8}) + (\frac{- 1}{3} \times \frac{- 9}{7}) - (\frac{2}{1} \times \frac{25}{14})$

x	$5$	$10$	$15$	$20$	$25$	$30$
f	$14$	$25$	$37$	$16$	$8$	$5$

\frac{9}{10} \times \frac{5}{9} \times \frac{15}{25} =

\frac{x}{10}

Join BYJU'S Learning Program