$1.5$ g $C d C l_{2}$ was found to contain $0.9$ g Cd. Calculate the atomic weight of Cd.

118

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112

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106.5

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53.25

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Solution

The correct option is C 106.5
$\frac{W t . o f C d C l_{2}}{W t . o f C d} = \frac{M o l . w t . o f C d C l_{2}}{A t . w t . o f C d}$
$\frac{1.5}{0.9} = \frac{M + 71}{M}$

$M = 106.5$ g

Therefore, the correct option is $C$

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