Question

$1.5g$ of $CdC{l}_2$ was found to contain $0.9g$ of $Cd$. Calculate, the atomic weight of $Cd$.

• A. $118$
• B. $112$
• C. $106.5$
• D. $53.25$

Answer 1

The correct option is C $106.5$

% of $Cd$ in $CdC{l}_2=\frac{0.9}{1.5}\times 100=60$%
Therefore, % of $C{l}_2$ in $CdC{l}_2=100-60=40$%
$\because 40$% part $\left(C{l}_2\right)$ has atomic weight
$=2\times 35.5=71.0$
$\therefore 60$% part $\left(Cd\right)$ has weight weight
$=\frac{71.0\times 60}{40}$
$=106.5$.