1.5 litre of solution of normality N and 2.5 litres of 2M HCl are mixed together. The resultant solution has a normality of 5. The value N is:

6

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Solution

The correct option is B $10$
$N = \frac{N_{1} V_{1} + N_{2} V_{2}}{V_{1} + V_{2}}$

Valency factor of HCl is 1.

Given,

$N_{(R e s u l t a n t)} = 5$

$5 = \frac{N \times 1.5 + 2 \times 2.5}{1.5 + 2.5}$

$5 = \frac{(1.5 N + 5)}{4}$

$\Rightarrow 15 = 1.5 N$

$\Rightarrow N = 10$

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1.5 litre of solution of normality N and 2.5 litres of 2M HCl are mixed together. The resultant solution has a normality of 5. The value N is:

The correct option is B 10N=N1V1+N2V2V1+V2Valency factor of HCl is 1.Given, N(Resultant)=55=N×1.5+2×2.51.5+2.55=(1.5N+5)4⇒15=1.5N⇒N=10

The correct option is B $10$
$N = \frac{N_{1} V_{1} + N_{2} V_{2}}{V_{1} + V_{2}}$

Valency factor of HCl is 1.

Given,

$N_{(R e s u l t a n t)} = 5$

$5 = \frac{N \times 1.5 + 2 \times 2.5}{1.5 + 2.5}$

$5 = \frac{(1.5 N + 5)}{4}$

$\Rightarrow 15 = 1.5 N$

$\Rightarrow N = 10$