1.5 mol of $O_{2}$ combines with $M g$ to form the oxide $M g O$ . The mass of $M g$ (at. mass 24) that has combined is:

72 g

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36 g

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48 g

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24 g

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Solution

The correct option is A 72 g
$M g + \frac{1}{2} O_{2} \to M g O$
0.5 mole
0.5 mole of oxygen react with 1 mole of Mg
1.5 mole of oxygen react with $\frac{1.5}{0.5} = 3 m o l e$
$24 \times 3 = 72 g m$

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1.5 mol of $O_{2}$ combines with $M g$ to form the oxide $M g O$ . The mass of $M g$ (at. mass 24) that has combined is:

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