Question

$1.5276$ g of $Cd{Cl}_2$ was found to contain $0.9367$ g of Cd. The atomic mass of Cd is (to the nearest integer) :

Answer 1

Mass of Cd = $0.9367g$
$\therefore$ Mass of Cl in $Cd{Cl}_2=1.5276-0.9367=0.5909g$
For $Cd{Cl}_2$: Eq. of Cd = Eq. of Cl
$\frac{0.9367}{E_{Cd}}=\frac{0.5909}{35.5}$
$\therefore$ Eq. mass of Cd =$56.275$
$\therefore AtomicmassofCd=Eq.mass\times Valence$
$=56.275\times 2=112.55g{mol}^{-1}$
So, atomic mass of Cd is $113$ g.