Question

1.5276 g of $CdC{l}_2$ was found to contain 0.9367 g of cadmium.

Calculate the atomic mass of cadmium.

Answer 1

Given weight of $CaC{l}_2=1.5276$

Weight of cadmium $=0.9367$

$\therefore$ weight of chlorine $=1.5276-0.9367$

$=0.5909g$

Now

$\frac{weightofcadmium}{weightofchlorine}=\frac{Equivalentweightofcadmium}{Equivalentweightofchlorine}$

$\frac{0.9367}{0.5909}={\frac{x}{35.5}}_{\leftarrow Eqwtofchlorine}^{\leftarrow Eqwtofchlorine}$

$E\left(x\right)$ or Eq. wt of cadmium $=56.27$

Now Atomic Mass $=$ Equivalent weight $\times$ valency

$=56.27\times 2$

$=112.27\approx 1124$