1+6÷3−(4+5)×7=
9
−60
−17
20
Using BODMAS to solve the given expression, 1+6÷3−(4+5)×7 =1+6÷3−9×7 =1+2−9×7 =1+2−63 =3−63 =−60
1+6÷3−(4+5)×7= ____.
Verify the following :
(i) 37×(56+1213)=(37×56)+(37×1213) (ii) −154×(37+−125)=(−154×37)+(−154×−125) (iii) (−83+−1312)×56=(−83×56)+(−1312×56) (iv) −167×(−89+−76)=(−167×−89)+(−167×−76)
11+√2+1√2+√3+1√3+√4+1√4+√5+1√5+√6+1√6+√7+1√7+√8+1√8+√9=__________.