The correct option is B 60Using BODMAS to solve the given expression, 1 + 6 ÷ 3 (4 + 5) × 7 = 1 + 6÷ 3 (9) × 7 = 1 + 2 9 × 7 = 1 + 2 63 = 3 63 = 60 ...

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Standard IX

Mathematics

Division of Integers

1+6 ÷ 3-4+5 ×...

Question

$1 + 6 \div 3 - (4 + 5) \times 7 =$

\frac{27}{3}

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- 60

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-173

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20

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Solution

The correct option is B $- 60$
Using BODMAS to solve the given expression,
$1 + 6 \div 3 - (4 + 5) \times 7$
$= 1 + 6 \div 3 - (9) \times 7$
$= 1 + 2 - 9 \times 7$
$= 1 + 2 - 63$
$= 3 - 63$
$= - 60$

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Verify the following :

(i) $\frac{3}{7} \times (\frac{5}{6} + \frac{12}{13}) = (\frac{3}{7} \times \frac{5}{6}) + (\frac{3}{7} \times \frac{12}{13})$
(ii) $\frac{- 15}{4} \times (\frac{3}{7} + \frac{- 12}{5}) = (\frac{- 15}{4} \times \frac{3}{7}) + (\frac{- 15}{4} \times \frac{- 12}{5})$
(iii) $(\frac{- 8}{3} + \frac{- 13}{12}) \times \frac{5}{6} = (\frac{- 8}{3} \times \frac{5}{6}) + (\frac{- 13}{12} \times \frac{5}{6})$
(iv) $\frac{- 16}{7} \times (\frac{- 8}{9} + \frac{- 7}{6}) = (\frac{- 16}{7} \times \frac{- 8}{9}) + (\frac{- 16}{7} \times \frac{- 7}{6})$

$\frac{1}{1 + \sqrt{2}} + \frac{1}{\sqrt{2} + \sqrt{3}} + \frac{1}{\sqrt{3} + \sqrt{4}} + \frac{1}{\sqrt{4} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{6}} + \frac{1}{\sqrt{6} + \sqrt{7}} + \frac{1}{\sqrt{7} + \sqrt{8}} + \frac{1}{\sqrt{8} + \sqrt{9}} =$ __________.

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1+6÷3−(4+5)×7=

The correct option is B −60Using BODMAS to solve the given expression, 1+6÷3−(4+5)×7 =1+6÷3−(9)×7 =1+2−9×7 =1+2−63 =3−63 =−60

$1 + 6 \div 3 - (4 + 5) \times 7 =$

The correct option is B $- 60$
Using BODMAS to solve the given expression,
$1 + 6 \div 3 - (4 + 5) \times 7$
$= 1 + 6 \div 3 - (9) \times 7$
$= 1 + 2 - 9 \times 7$
$= 1 + 2 - 63$
$= 3 - 63$
$= - 60$