1.6 mA current flowing in conducting wire then the number of electrons flowing per second is

(a)

10^{11}

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(b)

10^{16}

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(c)

10^{19}

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(d)

10^{15}

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Solution

The correct option is B (b) $10^{16}$
The correct option is B

Given,

$I = 1.6 m A = 1.6 \times 10^{- 3}$

Since the charge on the electron is:

$e = 1.6 \times 10^{- 19} C, t = 1 s$

So, $N = \frac{I}{e} = \frac{q t}{e}$

Where N is the number of electrons flowing per second.

$= \frac{1.6 \times 10^{- 3}}{1.6 \times 10^{- 19}}$

$= 10^{16}$

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1.6 mA current flowing in conducting wire then the number of electrons flowing per second is

The correct option is B (b) 1016The correct option is BGiven,I=1.6mA=1.6×10−3Since the charge on the electron is:e=1.6×10−19C,t=1sSo, N=Ie=qteWhere N is the number of electrons flowing per second.=1.6×10−31.6×10−19=1016