Question

$1.6\text{g}$ of calcium and $2.6\text{g}$ of zinc when treated with an acid in excess separately produced the same amount of hydrogen gas. Find the equivalent weight of calcium, given zinc has an equivalent weight of $32.6\text{g}$.

• A. $17\text{g}$
• B. $40\text{g}$
• C. $27\text{g}$
• D. $20\text{g}$

Answer 1

The correct option is D $20\text{g}$

Let the equivalent weight of calcium be $M$
$\frac{\text{weight of the metal}}{\text{weight of hydrogen}}=\frac{\text{equivalent weight of the metal}}{\text{equivalent weight of hydrogen}}$

Since, weight of hydrogen produced is equal in both the cases

$\frac{\text{weight of calcium}}{\text{equivalent weight of calcium}}=\frac{\text{weight of zinc}}{\text{equivalent weight of zinc}}$
$\Rightarrow \frac{1.6}{M}=\frac{2.6}{32.6}$
On solving, $M=20.06\sim 20\text{g}$