Question

$1.60\text{g}$ of a metal $A$ and $0.96\text{g}$ of a metal $B$ when treated with excess of dilute acid, separately, produced the same amount of hydrogen. Calculate the equivalent weight of $A$ if the equivalent weight of $B$ is $12$

Answer 1

${\text{Number of Equivalents}}_{\text{metal A}}={\text{Number of Equivalent}}_{\text{metal B}}$
$\frac{1.60}{{\text{equivalent weight}}_A}=\frac{0.96}{12}$
$\Rightarrow {\text{Equivalent weight}}_A=\frac{1.6\times 12}{0.96}=20$