1.64 g of a mixture of CaCO3 and MgCO3 was dissolved in 50 mL of 0.8MHCl. The excess of acid required 16 mL of 0.25MNaOH for neutralization. Calculate the percentage of CaCO3 in the sample.
A
51%
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B
75%
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C
49%
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D
25%
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Solution
The correct option is B49% The balanced reaction is as follows: CaCO3+2HCl→CaCl2+H2O+CO2 x2x MgCO3+2HCl→MgCl2+H2O+CO2 y2y 2x+2y=(50×0.8−16×0.25)1000⇒x+y=0.018.......(1) x×100+y×84=1.64 ........(2)