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Question

1.64 g of a mixture of CaCO3 and MgCO3 was dissolved in 50 mL of 0.8 M HCl. The excess of acid required 16 mL of 0.25 M NaOH for neutralization. Calculate the percentage of CaCO3 in the sample.

A
51%
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B
75%
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C
49%
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D
25%
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Solution

The correct option is B 49%
The balanced reaction is as follows:
CaCO3+2HClCaCl2+H2O+CO2
x 2x
MgCO3+2HClMgCl2+H2O+CO2
y 2y
2x+2y=(50×0.816×0.25)1000x+y=0.018.......(1)
x×100+y×84=1.64 ........(2)
%CaCO3=x×1001.64×100=48.78%
%MCO3=52.22%

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