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Byju's Answer
Standard X
Chemistry
Mole Concept
1.7 gm of PH3...
Question
1.7 gm of PH
3
was kept in a sealed tube. Find out-
- the no of moles of PH
3
-no of atoms present
-no of electrons present in it
-no of neutrons present in it
-no of molecules of PH
3
Open in App
Solution
Number of moles of PH
3
N
u
m
b
e
r
o
f
m
o
l
e
s
=
G
i
v
e
n
m
a
s
s
M
o
l
e
c
u
l
a
r
m
a
s
s
=
1
.
7
34
=
0
.
05
m
o
l
e
s
N
o
o
f
a
t
o
m
s
=
m
o
l
e
s
×
a
v
o
g
a
d
r
o
n
u
m
b
e
r
×
n
o
o
f
a
t
o
m
s
i
n
P
H
3
=
0
.
05
×
6
.
023
×
10
23
×
4
=
1
.
2046
×
10
23
a
t
o
m
s
N
o
o
f
m
o
l
e
c
u
l
e
s
=
m
o
l
e
s
×
a
v
o
g
a
d
r
o
n
u
m
b
e
r
=
0
.
05
×
6
.
023
×
10
23
=
0
.
3012
×
10
23
N
o
o
f
e
l
e
c
t
r
o
n
s
=
N
u
m
b
e
r
o
f
a
t
o
m
s
×
n
u
m
b
e
r
o
f
e
l
e
c
t
r
o
n
s
i
n
P
H
3
=
1
.
2046
×
10
23
×
(
15
+
3
)
(
n
o
o
f
e
l
e
c
t
r
o
n
s
i
n
P
=
15
a
n
d
H
=
1
)
=
18
.
442
×
10
23
e
l
e
c
t
r
o
n
s
N
o
o
f
n
e
u
t
r
o
n
s
=
N
u
m
b
e
r
o
f
a
t
o
m
s
×
n
u
m
b
e
r
o
f
n
e
u
t
r
o
n
s
i
n
P
H
3
=
1
.
2046
×
10
23
×
(
16
+
0
)
(
n
o
o
f
n
e
u
t
r
o
n
s
i
n
P
=
16
a
n
d
H
=
0
)
=
19
.
27
×
10
23
n
e
u
t
r
o
n
s
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Similar questions
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gas.
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Find the no. of neutrons in an atom if its mass no. is 27 and has 13 electrons in neutral state.
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