$1 - 8 p^{3}$ in the factor form is

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Solution

$1 - 8 p^{3} = 1^{3} - {(2 p)}^{3}$ is of the form $a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$

$= (1 - 2 p) (1 + 2 p + 4 p^{2})$

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