MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Gold Number

1.82 g of a m...

Question

1.82 g of a metal requires 32.5 ml of 1 N HCL to dissolve it. What is the equivalent weight of metal?

Open in App

Solution

Suggest Corrections

thumbs-up

13

Similar questions

1 g

of a metal required

50 m L

0.5 N H C l

to dissolve it. The equivalent mass of the metal is:

Q. To dissolve 0.9 g metal, 100 mL of 1 N

H C l

is used. What is the equivalent weight of the metal?

Q. To dissolve 0.9 gm metal 100 ml of 1 N HCl is used. what is the equivalent wt. of metal?

1

g of the carbonate of a metal was dissolved in

25

1 N

H C l

. The resulting liquid required

5

1 N

N a O H

for neutralisation. The Equivalent weight of the metal carbonate is:

1.0 g

carbonate of a metal was dissolved in

50 m L N / 2 H C l

solution. The resulting liquid required

25 m L

N / 5 N a O H

solution to neutralise it completely. Calculate the equivalent mass of the metal carbonate.

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Infections

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon