Question

$1.8g$ metal was deposited by a current of $3$ amp for $50$ min. Eq.wt of the metal is:

• A. $0.5$
• B. $25.8$
• C. $19.3$
• D. $30.7$

Answer 1

The correct option is C $19.3$

Weight of metal deposited $=1.8$ $g$

Now, $Q=I\times t$

$⟹Q=\left(3\right)\left(50\right)\left(60\right)$

$⟹Q=9000$ $C$

$\therefore Equivalentweight=96500\times \left(\frac{Weightofmetal}{Charge\left(Q\right)}\right)$

$⟹Equivalentweight=96500\times \frac{1.8}{9000}=19.3$ $g$