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Dividing a Monomial by a Monomial

1 - 8z 3 in ...

Question

1 - 8z $^{3}$ in the factor form is

(1 + 2z)(1 + 2z - 4z

^{2}

)

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(1 + 2z)(1 - 2z + 4z

^{2}

)

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(1 - 2z)(1 + 2z + 4z

^{2}

)

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(1 + 2z)(1 + 2z + 4z

^{2}

)

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Solution

The correct option is C (1 - 2z)(1 + 2z + 4z $^{2}$ )
1 - 8z $^{3}$ = (1) $^{3}$ - (2z) $^{3}$
= (1 - 2z)(1 + 2z + 4z $^{2}$ )

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