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Question

1: A perfect square number has four digits, none of which is zero. The digits from left to right have values that are even, even, odd, even. Find the number.

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Solution


If the number is EEOE then it's square root has possiblity as shown below,        OE  O EEOE¯       - O            EE     -OE                --                             ×      So the probable numbers are, 34,36,3852,54,56,5872,74,76,6892,94,96,98Now square of   34,36,38 and 72,74,76,68 will start with 1 and 5 so this will not follow EEOE, so we are left with, 52,54,56,5892,94,96,98Now we want last two digit as OE so this is possible when last digit is either 4 and 6 in the above 8 possibilities.So we will be left with54,5694,96Out of these 4 after squaring we can say that 94=8836, will follow the conditions.

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