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Question

1. A ray of light incident at an angle of incidence 48° on a prism of refracting angle 60° suffers minimum deviation. Calculate the angle of minimum deviation.
[Hint : δmin = 2i – A]

2. What should be the angle of incidence for a ray of light which suffers minimum deviation of 36° through an equilateral prism?
[Hint : A = 60°, i = (A + δmin) / 2]

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Solution

Dear Student ,
Here in this case from the given data we can write that ,
δmin=2i-AA=2i-δmin=96°-60°=36°
Regards

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