Question

1. A ray of light incident at an angle of incidence 48° on a prism of refracting angle 60° suffers minimum deviation. Calculate the angle of minimum deviation.
[Hint : δ_min = 2i – A]

2. What should be the angle of incidence for a ray of light which suffers minimum deviation of 36° through an equilateral prism?
[Hint : A = 60°, i = (A + δ_min) / 2]

Answer 1

Dear Student ,
Here in this case from the given data we can write that ,
$$\begin{gathered} {\delta }_{min}=2i-A \\ \Rightarrow A=2i-{\delta }_{min}=96°-60°=36° \end{gathered}$$
Regards