1 A submarine can descend from the water surface at the rate of 12 metre per minute after descending for 20 minutes it again rise by 30 meters what is its new position-

Dear student, The problem is simple. The submarine descends 12m in a minute. So it will descend 12×20 metres in 20 minutes. That is it has descended 240m. Now ...

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Byju's Answer

Standard VII

Mathematics

Application of Addition of Negative Numbers in Everyday Life Situation

1 A submarine...

Question

A submarine can descend from the water surface at the rate of $12$ meters per minute after descending for $20$ minutes it again rises by $30$ meters. what is its new position?

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Solution

The submarine descends $12 m$ in a minute. So it will descend $12 \times 20$ metres in $20$ minutes.
i.e it has descended $240 m .$

Now, it has risen $30$ metres from that point. So we have to subtract it as it has risen rather than descending.
(If it were descending, then we have to add, otherwise subtract when ascending in this case.)

So, it will be at a height of $240 - 30 = 210$ metres.

$∴$ The new position of the submarine is at $210 m$ from the sea level.

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A submarine can descend from the water surface at the rate of 12 meters per minute after descending for 20 minutes it again rises by 30 meters. what is its new position?

A submarine can descend from the water surface at the rate of $12$ meters per minute after descending for $20$ minutes it again rises by $30$ meters. what is its new position?