1-a-Write the equation in the ionic form - CuSO4 -aq- - Fe -s- - gt- FeSO4 -aq- - Cu -s- b- Divide the above equation into oxidation and reduction half reactions

Dear Student;1)The net ionic equation is: nbsp; Cu+2(aq) + Fe(s) – gt; Fe+2(aq) + Cu(s) nbsp; Any spectator ions are canceled out in a net ionic equ ...

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Standard XII

Chemistry

Properties and Uses of Calcium Oxide

1.a)Write the...

Question

1.a)Write the equation in the ionic form : CuSO4 (aq) + Fe (s) -----> FeSO4 (aq) + Cu (s)
b) Divide the above equation into oxidation and reduction half reactions

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Solution

Dear Student;1)The net ionic equation is:

Cu+2(aq) + Fe(s) --> Fe+2(aq) + Cu(s)

Any spectator ions are canceled out in a net ionic equation - those that do not take part in the reaction. In this case the sulfate ion (SO4-2). It is common on both sides of the reaction to balance the charge and plays no role other than to form ionic compounds with the Cu+2 and Fe+2 ions.
2)
Overall reaction: {Fe + CuSO4 → FeSO4 + Cu
Oxidation of iron: {Fe → Fe2+ + 2 e^-
Reduction of copper: {Cu2+ + 2 e- → Cu
SO4 2- is a “spectator ion”
Electrons released by iron are taken up by copper: a “redox couple”
Regards

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Similar questions

Q. Which of the following reactions will not occur? Why not?
(a)

{MgSO}_{4} (aq) + Cu (s) \underset{}{\to} {CuSO}_{4} (aq) + Mg (s)

(b)

{CuSO}_{4} (aq) + Fe (s) \underset{}{\to} {FeSO}_{4} (aq) + Cu (s)

(c)

{MgSO}_{4} (aq) + Fe (s) \underset{}{\to} {FeSO}_{4} (aq) + Mg (s)

Q. Dvide the following redox equations into oxidation half equation and reduction half equation.

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{C u}^{+} (a q)

is unstable in solution and undergoes simultaneous oxidation and reduction, according to the reaction

2 {C u}^{+} (a q) ⇌ {C u}^{2 +} (a q) + C u (s)

Choose correct

E

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and

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Q. Chemical equation for the reaction between

C u S O_{4}

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C u S O_{4} + F e \to F e S O_{4} + C u

(a) Write the reduction reaction taking place here.
(b) Give reason for the displacement of Cu by Fe from

C u S O_{4}

solution.

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1.a)Write the equation in the ionic form : CuSO4 (aq) + Fe (s) -----> FeSO4 (aq) + Cu (s) b) Divide the above equation into oxidation and reduction half reactions

1.a)Write the equation in the ionic form : CuSO4 (aq) + Fe (s) -----> FeSO4 (aq) + Cu (s)
b) Divide the above equation into oxidation and reduction half reactions