Question

1 ampere current is passed for 60 seconds into an electrolytic cell. Number of electrons that pass through the solution is :

• A. $6.0\times 10$${}^{23}$
• B. $1.2\times 10$${}^{24}$
• C. $37.5\times 10$${}^{19}$
• D. $7.48\times 10$${}^{21}$

Answer 1

The correct option is C $37.5\times 10$${}^{19}$

$Totalcharge=t\times I=60\times 1=60C$

$No.of{e}^{-}=\frac{totalcharge}{chargeon1e^{-}}$$=\frac{60}{1.6\times {10}^{-19}}$

$=37.5\times {10}^{19}electrons$

Option C is correct.