$1 - b u t y n e$ on oxidation with hot alkaline $K M n O_{4}$ would yield which of the following as end product?

C H_{3} C H_{2} C H_{2} C O O H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} C H_{2} C O O H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} C H_{2} C O O H + C O_{2} + H_{2} O

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C H_{3} C H_{2} C O O H + H C O O H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $C H_{3} C H_{2} C O O H + C O_{2} + H_{2} O$
$C H_{3} C H_{2} C \equiv C H H o t K M n O_{4} (a l k) - ---------- \to C H_{3} C H_{2} C O O H + H C O O H C H_{3} C H_{2} C O O H + C O_{2} + H_{2} O$

Suggest Corrections

Similar questions

K M n O_{4}

K M n O_{4}

K M n O_{4}

C H_{3} C H_{2} C O O H

r e d P - -- \to C l_{2}

- ----- \to A l c . K O H

C H_{3} C H_{2} C O O H C l_{2}, a l c o h o l i c K O H - ----------- \to r e d P

Join BYJU'S Learning Program