$1 - B u t y n e$ on reaction with hot alkaline $K M n O_{4}$ gives:

C H_{3} C H_{2} C H_{2} C O O H

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C H_{3} C H_{2} C O O H

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C H_{3} C H_{2} C O O H + C O_{2}

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C H_{3} C H_{2} C O O H + H C O O H

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Solution

The correct option is D $C H_{3} C H_{2} C O O H + C O_{2}$
$C H_{3} C H_{2} C \equiv C H h o t - ---------- \to a l k a l i n e K M N O_{4} C H_{3} C H_{2} C O O H + C O_{2} + H_{2} O$
Alkaline $K M n O_{4}$ oxidizes the 1-butyne to acetaldehyde and carbon dioxide.

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