1 Calculate relative density of a metal having density 10-8 - 103 kg - m 3 if density of water is 103 kg - m 3- -Ans - 10-8-2 A force of 1000 N is applied over an area 50 cm - 20 cm- What is the pressure acting at the bottom- -Ans- -10000 N - m 2-

(1) Density of a metal = 10.8103 kg/m3 Density of water = 103 kg/m3 Relative density of metal =..? (2) Force = 1000N Area = 50 cm20 cm = 0.5 m 0.2 m Pres ...

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Standard IX

Physics

Relative Density

1 Calculate r...

Question

(1) Calculate relative density of a metal having density 10.8 × 10³kg/m³if density of water is 10³kg/m³. [Ans : 10.8]

(2) A force of 1000 N is applied over an area 50 cm × 20 cm. What is the pressure acting at the bottom? [Ans : 10000 N/m²]

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Solution

_{(1) Density of a metal =}10.810³_kg/_m³

_{Density of water =}10³_kg/_m³

_{Relative density of metal =..?}

_{(2) Force = 1000N}

_{Area = 50}_cm20 cm = 0.5 m 0.2 m

_{Pressure on the bottom =………?}

_{Pressure on the bottom = 10,000 N/}_m²

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(1) Calculate relative density of a metal having density 10.8 × 103 kg/m3 if density of water is 103 kg/m3. [Ans : 10.8] (2) A force of 1000 N is applied over an area 50 cm × 20 cm. What is the pressure acting at the bottom? [Ans : 10000 N/m2]

(1) Density of a metal = 10.8103 kg/m3 Density of water = 103 kg/m3 Relative density of metal =..? (2) Force = 1000N Area = 50 cm20 cm = 0.5 m 0.2 m Pressure on the bottom =………? Pressure on the bottom = 10,000 N/m2

(1) Calculate relative density of a metal having density 10.8 × 10³kg/m³if density of water is 10³kg/m³. [Ans : 10.8]

(2) A force of 1000 N is applied over an area 50 cm × 20 cm. What is the pressure acting at the bottom? [Ans : 10000 N/m²]

_{(1) Density of a metal =}10.810³_kg/_m³

_{Density of water =}10³_kg/_m³

_{Relative density of metal =..?}

_{(2) Force = 1000N}

_{Area = 50}_cm20 cm = 0.5 m 0.2 m

_{Pressure on the bottom =………?}

_{Pressure on the bottom = 10,000 N/}_m²