1)carbon has,3 isotopes of atomic mass unit 12. 0 u and 13. 0 u and 14 u the relative abundance of these three isotopes are 98. 8 9 and 1. 10 and 2x10-10 respectively find out the average atomic mass of carbon?

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Solution

average atomic mass = ∑(relative abundance x mass of isotope)

Molar mass of carbon
= Σ isotopic mass x Relative abundance / Σ Relative abundance
= 0.98892 X (12 U) + 0.01108 X (13.0033 u) + 2 x10– 12 x (14.00317 u)
= 12.011 u.

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1)carbon has,3 isotopes of atomic mass unit 12. 0 u and 13. 0 u and 14 u the relative abundance of these three isotopes are 98. 8 9 and 1. 10 and 2x10-10 respectively find out the average atomic mass of carbon?

average atomic mass = ∑(relative abundance x mass of isotope) Molar mass of carbon = Σ isotopic mass x Relative abundance / Σ Relative abundance = 0.98892 X (12 U) + 0.01108 X (13.0033 u) + 2 x10– 12 x (14.00317 u) = 12.011 u.

average atomic mass = ∑(relative abundance x mass of isotope)

Molar mass of carbon
= Σ isotopic mass x Relative abundance / Σ Relative abundance
= 0.98892 X (12 U) + 0.01108 X (13.0033 u) + 2 x10– 12 x (14.00317 u)
= 12.011 u.