Question

$1cc$ of $0.1NHCl$ is added to $99cc$ solution of $NaCl$. The $pH$ of the resulting solution will be:

• A. $7$
• B. $3$
• C. $4$
• D. $1$

Answer 1

Answer: (B)

$3$

$HCl+NaCl$

$1$ mL of $0.1NHCl$ is added to $99$ mL solution of $NaCl$.

Total volume of solution after adding $HCl=100$ mL

$\left[H^{+}\right]=\frac{0.1}{100}M=0.001M$

$pH=-log\left(0.001\right)$

So, $pH=3$