Question

$1+\frac{1}{3+\frac{1}{3+\frac{1}{3}}}÷\left(\frac{1}{3}+10\frac{2}{3}of\frac{1}{11}\right)$ is equal to $2$.

• A. True
• B. False

Answer 1

The correct option is B False

We have,

$1+\frac{1}{3+\frac{1}{3+\frac{1}{3}}}÷\left(\frac{1}{3}+10\frac{2}{3}of\frac{1}{11}\right)$

$\Rightarrow 1+\frac{1}{3+\frac{3}{10}}÷\left(\frac{1}{3}+\frac{32}{3}\times \frac{1}{11}\right)$

$\Rightarrow 1+\frac{10}{33}÷\left(\frac{1}{3}+\frac{32}{33}\right)$

$\Rightarrow \frac{43}{33}÷\left(\frac{11+32}{33}\right)$

$\Rightarrow \frac{43}{33}÷\left(\frac{43}{33}\right)$

$\Rightarrow \frac{43}{33}\times \left(\frac{33}{43}\right)$

$\Rightarrow 1$

Hence, this is the answer.