1– Chloro-butane on reaction with alc. KOH gives

1 – butane

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1 – butanol

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2 – butane

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2 – butanol

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Solution

The correct option is A 1 – butane
$C H_{3} C H_{2} C H_{2} C H_{2} C l A l c . K O H - ----- \to C H_{3} C H_{2} C H = C H_{2} B u t - 1 - e n e$

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