Question

$1c{m}^3$ of $N_{2}O$ at S.T.P. contains :

• A. $2.653\times {10}^{23}$ molecules
• B. $2.653\times {10}^{19}$molecules
• C. $2.653\times {10}^{23}$ atoms
• D. $2.653\times {10}^{19}$atoms

Answer 1

Answer: (B)

$2.653\times {10}^{19}$molecules

1 mole of $N_{2}O$ at STP will have a volume of 22400 $c{m}^3$

No. of moles of $N_{2}O$ in 1 $c{m}^3=\frac{1}{22400}$

No. of molecules $=\frac{6.023\times {10}^{23}}{22400}$

$=2.653\times {10}^{19}$ molecules

Hence the correct option is B.