1. Define acceleration due to gravity.
2. Calculate the value of acceleration due to gravity on the surface of the moon. (Given: Mass of the moon $= 7.4 \times 10^{22} k g$ ; Radius of the moon = $1740 k m$ ; $G = 6.7 \times 10^{- 11} N m^{2} k g^{- 2}$ ) [3 MARKS]

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Solution

Definition: 1 Mark
Problem: 2 Marks

1. The acceleration gained by an object because of gravitational force is called its acceleration due to gravity. The value of acceleration due to gravity is $g = 9.8 m s^{- 2}$ .

2. Given, gravitational constant, $G = 6.7 \times 10^{- 11} N m^{2} k g^{- 2}$ ,
mass of the moon, $M = 7.4 \times 10^{22} k g$ , and
radius of the moon, $R = 1740 k m = 1740 \times 10^{3} m$
Let $g$ be the acceleration due to gravity.
We know, $g = G \times \frac{M}{R^{2}}$
$g = \frac{6.7 \times 10^{- 11} \times 7.4 \times 10^{22}}{(1740 \times 10^{3})^{2}}$
$\Rightarrow g = 1.63 m s^{- 2}$

Thus, the acceleration due to gravity, g, on the surface of the moon is $1.63 m s^{- 2}$

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1. Define acceleration due to gravity. 2. Calculate the value of acceleration due to gravity on the surface of the moon. (Given: Mass of the moon =7.4×1022 kg; Radius of the moon =1740 km; G=6.7×10−11 Nm2kg−2) [3 MARKS]

1. Define acceleration due to gravity.
2. Calculate the value of acceleration due to gravity on the surface of the moon. (Given: Mass of the moon $= 7.4 \times 10^{22} k g$ ; Radius of the moon = $1740 k m$ ; $G = 6.7 \times 10^{- 11} N m^{2} k g^{- 2}$ ) [3 MARKS]