$1 \frac{2}{6} \times 2 \frac{3}{6} =$

\frac{3}{2}

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\frac{1}{12}

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\frac{10}{3}

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Solution

The correct option is C $\frac{10}{3}$
$1 \frac{2}{6} \times 2 \frac{3}{6} = \frac{6 \times 1 + 2}{6} \times \frac{2 \times 6 + 3}{6}$

$= \frac{8}{6} \times \frac{15}{6} = \frac{120}{36}$

$\Rightarrow \frac{120}{36} = \frac{2 \times 2 \times 2 \times 3 \times 5}{2 \times 2 \times 3 \times 3} = \frac{10}{3}$

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Similar questions

If $\frac{6^{6} + 6^{6} + 6^{6} + 6^{6} + 6^{6} + 6^{6}}{3^{6} + 3^{6} + 3^{6}} \div \frac{4^{6} + 4^{6} + 4^{6} + 4^{6}}{2^{6} + 2^{6}} = 2^{n}$ then find the value of $n$ .

Q. Find the value of

^{6} C_{0} .^{12} C_{6} -^{6} C_{1} .^{11} C_{6} +^{6} C_{2} .^{10} C_{6} +^{6} C_{2} .^{10} C_{6} -^{6} C_{3} .^{9} C_{6} +^{6} C_{4} .^{8} C_{6} -^{6} C_{5} .^{7} C_{6} +^{6} C_{6} .^{6} C_{6}

\sqrt{6 + \sqrt{6 + \sqrt{6 + \sqrt{6 + . . . .}}}}

= ?

Mark the correct option:

The number is equal to

A. 6⁶

\sqrt{6 + \sqrt{6 + \sqrt{6 + \sqrt{6 + . . . . . t o \infty}}}} =

........

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126×236=

The correct option is C 103126×236=6×1+26×2×6+36 =86×156=12036 ⇒12036=2×2×2×3×52×2×3×3=103

$1 \frac{2}{6} \times 2 \frac{3}{6} =$