$1 \div 0 =$ ___

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Undefined

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Solution

The correct option is C
Undefined

$1 \div 0$ means $1$ item is to be divided into $0$ parts. This makes no sense!
Thus, division by zero is undefined.

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Similar questions

$1 \div 0 =$

⎡ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & - 1 & 0 & 0 & 0 0 & 0 & 1 & - 1 & 0 0 & 1 & - 1 & 0 & 0 - 1 & 0 & 0 & 0 & 1 0 & 0 & 0 & 1 & - 1 \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎦

⎡ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 0 & 0 & 0 & 1 0 & 1 & 1 & 1 & 0 0 & 1 & 1 & 1 & 0 0 & 1 & 1 & 1 & 0 1 & 0 & 0 & 0 & 1 \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎦

P_{1} = ∣ ∣ ∣ ∣ \begin{matrix} 1 & 0 & 0 0 & 1 & 0 0 & 0 & 1 \end{matrix} ∣ ∣ ∣ ∣,

P_{2} = ∣ ∣ ∣ ∣ \begin{matrix} 1 & 0 & 0 0 & 0 & 1 0 & 1 & 0 \end{matrix} ∣ ∣ ∣ ∣,

P_{3} = ∣ ∣ ∣ ∣ \begin{matrix} 0 & 1 & 0 1 & 0 & 0 0 & 0 & 1 \end{matrix} ∣ ∣ ∣ ∣,

P_{4} = ∣ ∣ ∣ ∣ \begin{matrix} 0 & 1 & 0 0 & 0 & 1 1 & 0 & 0 \end{matrix} ∣ ∣ ∣ ∣,

P_{5} = ∣ ∣ ∣ ∣ \begin{matrix} 0 & 0 & 1 1 & 0 & 0 0 & 1 & 0 \end{matrix} ∣ ∣ ∣ ∣,

P_{6} = ∣ ∣ ∣ ∣ \begin{matrix} 0 & 0 & 1 0 & 1 & 0 1 & 0 & 0 \end{matrix} ∣ ∣ ∣ ∣,

X = 6 \sum k = 1 P_{k} ⎡ ⎢ ⎣ \begin{matrix} 2 & 1 & 3 1 & 0 & 2 3 & 2 & 1 \end{matrix} ⎤ ⎥ ⎦ P_{k}^{T},

P_{k}^{T}

P_{k} .

u_{n} = ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ \begin{matrix} a_{1} & 1 & 0 & 0 & . . . & . . . & 0 - 1 & a_{2} & 1 & 0 & . . . & . . . & 0 0 & - 1 & a_{3} & 1 & . . . & . . . & 0 . . . & . . . & . . . & . . . & . . . & . . . & . . . 0 & 0 & . . . & . . . & - 1 & a_{n - 1} & 1 0 & 0 & . . . & . . . & 0 & - 1 & a_{n} \end{matrix} ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣ ∣

u_{n} = a_{n} u_{n - 1} + u_{n - 2}

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