1dm3 of an ideal gas at a pressure of 10 bar expands reversibly and isothermally to final volume of 20 litre. What will be the magnitude of heat involved in the process (in kJ)? (Take ln 20 = 3)
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Solution
ΔU=0⇒q=−w
w=−nRTlnV2V1=−P1V1 ln V2V1
=−10×1ln201
=−10×3 bar - lit
=−3×105×10−3=−300J Hence, the required answer is 0.3 kJ.