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Question
1 dm3 of an ideal gas at a pressure of 10 bar expands reversibly and isothermally to final volume of 10 litre. What will be the heat absorbed in the process? (ln 10 = 2.3)
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Solution
The correct option is C 2.3 kJ
ΔU=0⇒q=−w
w=−nRT ln V2V1=−P1V1 In V2V1
=−10×1 ln 101
=−10×2.3 bar - lit
=−23×105×10−3=−2300J
Hence, the required answer is 2.3 kJ.
ΔU=0⇒q=−w
w=−nRT ln V2V1=−P1V1 In V2V1
=−10×1 ln 101
=−10×2.3 bar - lit
=−23×105×10−3=−2300J
Hence, the required answer is 2.3 kJ.
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