wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

(1) Draw the graph of y = x2 and y = 2x + 3 and hence solve the equation x2 − 2x − 3 = 0.

(2) Draw the graph of y = 2x2 and y = 3 − x and hence solve the equation 2x2 + x − 3 = 0.

(3) Draw the graph of y = 2x2 and y = 3 + x and hence solve the equation 2x2 − x − 3 = 0.

Open in App
Solution

(1) We need to solve the equations.

We make the following table for.

Plot the points (0, 0), (1, 1), (–1, 1), (2, 4) and (–2, 4) and join them smoothly

We make the following table for.

Plot the points (0, 3), (1, 5), (–1, 1), (2, 7) and (–2, –1) and join them.

From the intersection of the lineand the curve, draw perpendiculars to the x-axis.

It can be noted that:

Hence, the roots of are.

(2) We need to solve the equations

We make the following table for.

Plot the points (0, 0), (1, 2), (–1, 2), (2, 8) and (–2, 8) and join them smoothly.

We make the following table for.

Plot the points (0, 3), (1, 2), (–1, 4), (2, 1) and (–2, 5) and join them.

From the intersection of the lineand the curve, draw perpendiculars to the x-axis.

It can be noted that:

Hence, the roots of are.

(3) We need to solve the equations

We make the following table for.

Plot the points (0, 0), (1, 2), (–1, 2), (2, 8) and (–2, 8) and join them smoothly.

We make the following table for.

Plot the points (0, 3), (1, 4), (–1, 2), (2, 5) and (–2, 1) and join them.

From the intersection of the lineand the curve, draw perpendiculars to the x-axis.

It can be noted that:

Hence, the roots of are.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Graphical Solution
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon