1. "Find the time taken by the particle in going from x=0 to x=A/2 where is the amplitude." Why can't we use cosine component instead of sine component.

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Q. A particle is performing

S H M

of amplitude

A

and time period

T

. Find the time taken by the particle to go from

x = 0

x = \frac{A}{2}

Q. A particle is performing SHM of amplitude "A" and time period "T". Find the time taken by the particle to go from 0 to A /

\sqrt{2}

Q. Displacement-time equation of a particle executing SHM is :

X = A s i n (ω t + \frac{π}{6})

. Time taken by the particle to go directly from

X = - \frac{A}{2}

X = + \frac{A}{2}

Q. The motion of a particle executing simple harmonic motion is described by the displacement function

x (t) = A cos (w t + ϕ)

. If the initial ( t= 0) position of the particle is 1 cm and its initial velocity is w cm/s, what are its amplitude and initial phase angle? The angular frequency of the particle is

π s^{- 1}

. If instead of the cosine function , we choose the sine function to describe the SHM

x = B sin (w t + α)

, what are the amplitude and initial phase of particle with the above initial conditions?

The motion of a particle executing simple harmonic motion is described by the displacement function,

x (t) = A cos (ωt + φ).

If the initial (t = 0) position of the particle is 1 cm and its initial velocity is ω cm/s, what are its amplitude and initial phase angle? The angular frequency of the particle is π s^–1. If instead of the cosine function, we choose the sine function to describe the SHM: x = B sin (ωt + α), what are the amplitude and initial phase of the particle with the above initial conditions.

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