If e is the electric field intensity of an electrostatic field then the electrostatic energy density is proportional to
1)e
2)e×e
3)1/e×e
4)e×e×e
Answer is 2
Let I =∫exe4x+e2x+1dx.J=∫e−xe−4x+e−2x+1dx,Then, for an arbitrary constant c, the value of J-I equals