Question

$1\frac{1}{3}+2\frac{1}{6}-3\frac{1}{9}=1÷?$

• A. $2\frac{4}{7}$
• B. $5\frac{2}{7}$
• C. $2\frac{1}{3}$
• D. $3\frac{1}{7}$
• E. None of the above

Answer 1

The correct option is A $2\frac{4}{7}$

Here, $1\frac{1}{3}+2\frac{1}{6}-3\frac{1}{9}=1÷x$
$\Rightarrow \frac{4}{3}+\frac{13}{6}-\frac{28}{9}=1÷x$
$\Rightarrow \frac{24+39-56}{18}=1÷x$
$\Rightarrow \frac{7}{18}=1÷x$
$\Rightarrow x=\frac{18}{7}=2\frac{4}{7}$