Question

$1\frac{3}{25}+\frac{7}{20}-\frac{2}{5}$

Answer 1

Step1:- First convert the mixed fraction into an improper fraction:

$1\frac{3}{25}=\frac{28}{25}$

Step 1:- Make the denominator of both fractions same.

Multiply $\frac{28}{25}$by $4$

$\frac{28}{25}$$=\frac{28\times 4}{25\times 4}=\frac{112}{100}$

Multiply $\frac{7}{20}$ by $5$.

$\frac{7}{20}$$=\frac{7\times 5}{20\times 5}=\frac{35}{100}$

Multiply $\frac{2}{5}$by $20$.

$\frac{2}{5}$$=\frac{2\times 20}{5\times 20}=\frac{40}{100}$

Step 2:- Add $\frac{112}{100}$ and $\frac{35}{100}$

$\frac{112}{100}+\frac{35}{100}=\frac{112+35}{100}=\frac{147}{100}$

Step 3:- Subtract $\frac{40}{100}$ from $\frac{147}{100}$

$\frac{147}{100}-\frac{40}{100}=\frac{147-40}{100}=\frac{107}{100}$

Step 4:- Convert the improper fraction into a mixed fraction.

$\frac{107}{100}$$=$$1\frac{7}{100}$

Hence, $1\frac{7}{100}$ is the required solution.