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Question

1 g H2 gas as STP is expanded so that volume is doubled. Hence, work done is


A

22.4 L atm

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B

5.6 L atm

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C

111.2 L atm

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D

1.135 kJ

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Solution

The correct option is D

1.135 kJ


At STP 1 gr of H2 = 12 mole of H2, will occupy 11.2 lit

Thus if volume is doubled= V2 V1 = 22.4 11.2 = 11.2 lit

W = p(V2 V1) = 1 × 11.2 lit atm (1 lit atm = 101.33) = 1.135 kJ


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