Question

1 g HCl and 1 g NaOH are mixed in 1 L water. The nature of resulting solution will be

Answer 1

moles of HCl in the solution = $$\begin{gathered} \frac{1\text{g}}{36.5{\text{gmol}}^{{}^{}\text{-1}}}=0.0274\text{mol} \\ \text{moles of NaOH in the solution}=\frac{1\text{g}}{40{\text{gmol}}^{\text{-1}}}=0.025\text{mol} \\ \text{As moles of acid is more than base, after neutralisation acid will} \\ \text{remain and hence the solution will be acidic.} \end{gathered}$$