1g mole of an ideal gas at STP is subjected to a reversible adiabatic expansion to double its volume. Find the change in internal energy (γ=1.4 )
A
11.695.5J
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B
769.5J
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C
1369.5J
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D
969.5J
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Solution
The correct option is B1369.5J As it is an adiabatic process we use T1Vγ−11=T2Vγ−12 or T2=T1Vγ−11Vγ−12=273(2)0.4=207K Change the Internal Energy ΔU=R(γ−1)(T1−T2) =8.31(273−207)1.4−1=1369.5J