1 g of 12C contains 6-022- 1023 atoms of Carbon-

The correct option is B FalseNo. of moles in 1 gm of carbon (12) = 112 No. of atoms = 112 #160; #160; × 6.022×10^23 ...

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Boyle's Law

1 g of 12C ...

Question

$1$ g of $^{12} C$ contains $6.022 \times 10^{23}$ atoms of Carbon.

True

No worries! We‘ve got your back. Try BYJU‘S free classes today!

False

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B False
No. of moles in $1$ gm of carbon $(12)$ $= \frac{1}{12}$
No. of atoms $= \frac{1}{12}$ $\times 6.022 \times 10^{23}$

Suggest Corrections

Similar questions

Q. 1 g of

^{12} C

contains

6.022 \times 10^{23}

atoms of the isotope.

1 g

^{12} C

contains

6.022 \times 10^{23}

atoms of the isotope.

Q. 12 g C-12 contains

6.022 \times 10^{23}

atoms of carbon.
(a)

6.022 \times 10^{23}

is known as .............
(b) Calculate the number of carbon atoms present in 48 g C-12.
(c) Which weighs more,

6.022 \times 10^{23}

molecules of

C O_{2}

6.022 \times 10^{23}

molecules of

H_{2} O

Q. Assertion :Both

138

g of

K_{2} C O_{3}

and

12

g of carbon have same number of carbon atoms. Reason: Both contain

1

g atom of carbon which contains

6.022 \times 10^{23}

carbon atoms.

One mole of any substance contains $6.022 \times 10^{23}$ atoms/molecules. Number of molecules of $H_{2} S O_{4}$ present in 100 mL of $0.02 M H_{2} S O_{4}$ solution is.............

(a) $12.044 \times 10^{20}$ molecules (b) $6.022 \times 10^{23}$ molecules

Join BYJU'S Learning Program

1 g of 12C contains 6.022×1023 atoms of Carbon.

The correct option is B FalseNo. of moles in 1 gm of carbon (12) =112No. of atoms =112 ×6.022×1023

$1$ g of $^{12} C$ contains $6.022 \times 10^{23}$ atoms of Carbon.

The correct option is B False
No. of moles in $1$ gm of carbon $(12)$ $= \frac{1}{12}$
No. of atoms $= \frac{1}{12}$ $\times 6.022 \times 10^{23}$