Question

1 g of a metal, having no variable valency, produces 1.67 g of its oxide when heated in air. Its carbonate contains 28.57% of the metal. How much oxide will be obtained by heating 1 g of the carbonate ?

• A. 0.4771
• B. 0.54
• C. 0.64
• D. 0.5321

Answer 1

The correct option is A 0.4771

100gm of metal carbonate will contain $=28.57g$ of metal

So 1gm of carbonate will have $=\frac{28.57}{100}=0.285gm$

$1gm$ of metal forms $=1.67gm$ of metal oxide

So, $0.285gm$ will form$=1.67\times 0.285=0.475gm$ of metal oxide