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Calorimetry

1 g of a meta...

Question

$1 g$ of a metal required $50 m L$ of $0.5 N H C l$ to dissolve it. The equivalent mass of the metal is:

25

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30

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20

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40

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Solution

The correct option is D $40$
$N o r m a l i t y = \frac{m a s s o f s o l u t e}{e q u i v a l e n t m a s s} \times v o l . (i n l i t r e s) N = 0.5, m a s s o f s o l u t e = 1 g, v o l u m e = 50 m l 0.5 = \frac{1}{e q . m a s s} \times \frac{1000}{50} e q . m a s s = 40 M o l e c u l a r m a s s = n f a c t o r \times e q . m a s s = 1 \times 40 M o l . m a s s = 40$

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