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Latent Heat of Vaporisation

1 g of ice at...

Question

1 g of ice at $0^{o} C$ is converted into steam at $100^{o} C$ . The amount of heat required to do so is

80 cal

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536 cal

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616 cal

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0.716 kcal

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Solution

The correct option is D 0.716 kcal
$H e a t r e q u i r e d = (h e a t r e q u i r e d t o c o n v e r t i c e a t 0^{o} C t o 100^{o} C)$ + $(H e a t r e q u i r e d t o c o n v e r t w a t e r t o s t e a m a t 100^{o} C)$
$= (1 \times 80 c a l) + (1 \times 1 \times 100) + (1 \times 536) = (180 + 536)$
$= 716 c a l . o r 0.716 k c a l .$

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