Question

$1$ g sample of alkaline earth metal reacts completely with $4.08$ g $H_{2}S{O}_4$ and yields an ionic product $MS{O}_4$. Find out the atomic mass of alkaline earth metal ($M$)?

• A. $9$
• B. $24$
• C. $40$
• D. $87$

Answer 1

Answer: (B)

$24$

The reaction is as follows:
$M+H_{2}S{O}_4\to MS{O}_4+H_2$
$\frac{MolesofM}{2}=\frac{Molesof{H}_{2}S{O}_4}{2}$
$\frac{1}{a}=\frac{4.08}{98}$
$a=\frac{98}{4.08}=24.01$
Therefore, the atomic mass of $M$ is $24$ g/mol.